Week 3
The reduced digit sum of 625 is calculated as follows:
6+2+5 = 13
1+3 = 4
Therefore, the reduced digit sum of 625 = 4
Given a certain number N, if the reduced digit sum of N is 1 then print “YES” otherwise print “NO”.
Input:
The first and only line of input will contain the number N.
Output:
“YES” If the reduced digit sum of N = 1
Otherwise,
“NO”
Example:
Input:
8686
Output:
YES
Grading System:
10 points for getting the correct output.
30 points for submitting the program with the least number of characters. (You will be given points relatively out of 30 depending on the least number of characters used and the number of characters used by you.)
Coding rules:
-
Please only use python to code your answers.
-
Send your entries as
.txtfiles and name them asName_Roll Number.txt
Deadline:
6th April, 7:00 PM
You have exactly 1 week to send in your entries.
Winning Entries:
Here are the winning codes !!
MS21 : Sparsha Ray MS21256
36 characters
print('YNEOS'[int(input())%9!=1::2])
MS20 : Harsh Raj MS20161, Sachin G Iyer MS20056
38 characters
print(["NO","YES"][int(input())%9==1])
MS19, MS18, MS17, Int PhD, PhD: Kaustav Sen MS19091
37 characters
print('NYOE S'[int(input())%9==1::2])